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1888 in tennis

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This page covers all the important events in the sport of tennis in 1888. It provides the results of notable tournaments throughout the year on both the men's and women's ILTF tennis circuits.[1]

Australian Open

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No event.

French Open

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Not a Grand Slam event.

Wimbledon

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Men's singles

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United Kingdom Ernest Renshaw defeated United Kingdom Herbert Lawford, 6–3, 7–5, 6–0 [2]

Women's singles

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United Kingdom Lottie Dod defeated United Kingdom Blanche Hillyard, 6–3, 6–3 [3]

Men's doubles

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United Kingdom Ernest Renshaw / United Kingdom William Renshaw defeated United Kingdom Patrick Bowes-Lyon / United Kingdom Herbert Wilberforce, 2–6, 1–6, 6–3, 6–4, 6–3 [4]

US Open

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Men's singles

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United States Henry Slocum defeated United States Howard Taylor 6–4, 6–1, 6–0

Women's singles

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United States Bertha Townsend defeated United States Ellen Hansell 6–3, 6–5

Men's doubles

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United States Oliver Campbell / United States Valentine Hall defeated United States Clarence Hobart / United States Edward MacMullen 6–4, 6–2, 6–2

Notes

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References

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  1. ^ Bud Collins (2010). The Bud Collins History of Tennis (2nd ed.). [New York]: New Chapter Press. pp. 454–483. ISBN 978-0942257700.
  2. ^ "Gentlemen's Singles Finals 1877-2016". wimbledon.com. Wimbledon Championships. Retrieved June 29, 2017.
  3. ^ "Ladies' Singles Finals 1884-2016". wimbledon.com. Wimbledon Championships. Retrieved June 29, 2017.
  4. ^ "Gentlemen's Doubles Finals 1884-2016". wimbledon.com. Wimbledon Championships. Retrieved June 29, 2017.
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