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1989 Asian Open
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| Tournament information | |
|---|---|
| Dates | 17–27 August 1989 |
| Venue | Channel 12 Studios |
| City | Bangkok |
| Country | Thailand |
| Organisation | WPBSA |
| Format | Ranking event |
| Total prize fund | £200,000[1] |
| Winner's share | £40,000[1] |
| Highest break | |
| Final | |
| Champion | |
| Runner-up | |
| Score | 9–6 |
1990 → | |
The 1989 555 Asian Open was a professional ranking snooker tournament that took place between 17 and 27 August 1989 at the Channel 12 Studios in Bangkok, Thailand.[2][3]
Stephen Hendry won the tournament by defeating James Wattana 9–6 in the final.[4]
Main draw
[edit]References
[edit]- ^ a b c Smith, Terry (28 August 1989). "Hendry new No 1". The Daily Telegraph. p. 21.
- ^ Sunley, Rob (28 June 1989). "Hallett joins Hearns' jet-set". Grimsby Evening Telegraph. p. 14.
- ^ "Asian Open, Asian Classic, Hong Kong Open". Chris Turner's Snooker Archive. Archived from the original on 16 February 2012. Retrieved 2 March 2018.
- ^ "Asian Open". Snooker Scene. Archived from the original on 24 January 2013. Retrieved 2 March 2018.
- ^ Hayton, Eric. Cuesport Book of Professional Snooker. pp. 158–159.