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Bucktown, Indiana
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Bucktown, Indiana | |
|---|---|
 Sullivan County's location in Indiana | |
  Bucktown Location in Sullivan County, Indiana | |
| Coordinates: 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W | |
| Country | United States |
| State | Indiana |
| County | Sullivan |
| Township | Jefferson |
| Elevation | 594 ft (181 m) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 47838 |
| Area codes | 812, 930 |
| GNIS feature ID | 431756 |
Bucktown is an unincorporated community in Jefferson Township, Sullivan County, in the U.S. state of Indiana.[2]
The community is part of the Terre Haute Metropolitan Statistical Area.
Geography
[edit]Bucktown is located at 38°59′41″N 87°15′36″W / 38.99472°N 87.26000°W.
References
[edit]- ^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved August 29, 2016.
- ^ "Bucktown, Indiana". Geographic Names Information System. United States Geological Survey. Retrieved August 5, 2017.
Municipalities and communities of Sullivan County, Indiana, United States | ||
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| Ghost towns | ||
| Footnotes | ‡This populated place also has portions in an adjacent county or counties | |
| This Sullivan County, Indiana location article is a stub. You can help Wikipedia by adding missing information. |